What you will understand
When an object is submerged in water, it displaces a certain amount of water. In response, the water exerts an upward force on it: this is Archimedes' buoyant force. The larger the volume of water displaced, the greater this force.
Scientific question
Question studied
Can the shape of an object change its buoyancy, even if its mass stays the same?
What we will compare
- A compact ball of modeling clay
- A boat made with exactly the same amount of clay
- Each shape's ability to float and support a load
Materials
Essential
- Modeling clay
- A large bowl or basin filled with water
- Some coins
- A spoon or a small strainer
- Something to note observations
To go further
- A measuring cup to measure displaced water
- A scale to know the mass used
- A towel to dry the clay between trials
Protocol
Results table
| Trial | Shape | Floats or sinks | Stability | Number of coins supported | Observations |
|---|---|---|---|---|---|
| 1 | Ball | 0 | |||
| 2 | Boat | ||||
| 3 | Improved boat |
Analysis questions
1. What happens with the modeling clay ball?
2. Why does the boat float better than the ball?
3. What does “displacing water” mean in this activity?
4. Which shape supports the most coins? Why?
Help to check your reasoning
- The compact ball often sinks quickly because it displaces too little water before being fully submerged.
- The boat floats better because its shape allows it to displace more water while remaining partially at the surface.
- The greater the volume of displaced water, the stronger Archimedes' buoyant force.
Conclusion
Scientific conclusion
With the same amount of modeling clay, the ball and the boat behave differently in water. The difference comes from their shape: the boat displaces more water before sinking, so the upward force exerted is greater.
Link to the real world
A steel boat can float not because steel is "light," but because its shape allows it to displace a large volume of water. Its average density, considering the air it contains, becomes compatible with floating.